$tan 203^{0} + tan 22^{0} + tan 203^{0} tan 22^{0} =$

-1

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Solution

The correct option is A -1
$tan 203^{o} + tan 22^{o} + tan 203^{o} tan 22^{o}$
$203 + 22 = 225$
$tan (203 + 22) = tan 225 = tan (180 + 45)$
$\frac{tan 203 + tan 22}{1 - tan 203 tan 22} = 1$
$tan 203 + tan 22 = 1 - tan 203 tan 22$
$tan 203 + tan 22 + tan 203 tan 22 = 1$ .

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