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Question

tan4θ+tan2θ is equal to

A
sec2sec4θ
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B
sec4θsec2θ
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C
sin4θsec2θ
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D
sin4θcos2θ
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Solution

The correct option is B sec4θsec2θ
tan4θ+tan2θ=tan2θ(tan2θ+1)
=(sec2θ1)sec2θ
=sec4θsec2θ

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