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Question

tan 7° tan 23° tan 60° tan 67° tan 83° + cot54°tan36° + sin 20° sec 70° − 2

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Solution

tan70tan230tan600tan670tan830+cot540tan360+sin200sec7002 =(tan600)(tan70tan830)(tan230tan670)+cot(900360)tan360+sin200sec(900200)2 =3{tan70tan(90070)}{tan230tan(900230)}+tan360tan360+sin200cosec2002 =3(tan70cot70)(tan230cot230)+1+sin2001sin2002 =3×(1×1)+1+1-2 =3×1 =3

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