$tan 9^{o} \times tan 27^{o} \times tan 63^{o} \times tan 81^{o} =$

4

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3

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2

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1

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Solution

The correct option is D $1$
$tan 9^{\circ} . tan 27^{\circ} . tan 63^{\circ} . tan 81^{\circ} = tan (90^{\circ} - 81^{\circ}) . tan (90^{\circ} - 63^{\circ}) . tan 63^{\circ} . tan 81^{\circ} = cot 81^{\circ} . cot 63^{\circ} . tan 63^{\circ} . tan 81^{\circ} = 1$

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