Question

$\tan (90-\theta )$ is equivalent to

• A. $\cos \theta$
• B. $\sin \theta$
• C. $(\sin \theta +\cos \theta )$
• D. $\cot \theta$

Answer 1

The correct option is D $\cot \theta$

In the figure,
$\tan ({90}^{\circ }-\theta )=\frac{x}{y}$ and $\cot \theta =\frac{x}{y}$

So $\tan (90-\theta )=\cot \theta$

So $\cot \theta$ is correct.