Question

$\tan A+\cot ({180}^o+A)+\cot ({90}^o+A)+\cot ({360}^o-A)=$

• A. 0
• B. $2\tan A$
• C. $2\cot A$
• D. $2(\tan A-\cot A)$

Answer 1

The correct option is A 0

$\tan A+\cot ({180}^o+A)+\cot ({90}^o+A)+\cot ({360}^o-A)$

we know that only in $1^{st}$ and $3^{rd}$ $\tan$ and $\cot$ are positive hence the given equation becomes

$=\tan A+\cot A-\tan A-\cot A=0$