Evaluate tan-11-x22x+cos-11-x21+x2=
π4
π2
π
0
Explanation for the correct option:
Find the value of the given Equation.
Consider the given Equation as
y=tan-11-x22x+cos-11-x21+x2→(i)
We know that,
cos-11-x21+x2=2tan-1x=tan-12x1-x2
Then, the equation (i) becomes
y=tan-11-x22x+tan-12x1-x2
Then,
y=tan-11-x22x+2x1-x21-1-x22x2x1-x2[∵tan-1A+tan-1B=tan-1A+B1-AB]y=tan-11-x22x+2x1-x21-1y=tan-11-x22x+2x1-x20y=tan-1∞y=π2
Hence, option (B) is the correct answer.