tan inverse x^2 + y^2 = a^2 find dy/dx

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Solution

solution-
tan inverse (x^2 + y^2) = a^2
x^2 + y^2 = tan(a^2)
differentiating both side with respect to x -
d/dx(x^2) + d/dx(y^2) = d/dx(a^2)
2x + 2ydy/dx = 0 (because d/dx(constant) = 0)
2ydy/dx = -2x
dy/dx = -2x/2y
dy/dx = -x/y

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