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Byju's Answer
Standard XII
Mathematics
Sin(A+B)Sin(A-B)
tan3A - tan2A...
Question
tan3A - tan2A -tanA is equal to
A
(a) tan3A tan2A tanA
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B
(b) -tan3A tan2A tanA
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C
(c) tanA tan2A - tan2A tan3A -tan3A tanA
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D
(d) none of these
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Solution
The correct option is
A
(a) tan3A tan2A tanA
tan3A tan2A tanA
3A=2A+A
⇒
t
a
n
3
A
=
t
a
n
(
2
A
+
A
)
=
t
a
n
2
A
+
t
a
n
A
1
−
t
a
n
2
A
t
a
n
A
⇒
t
a
n
3
A
−
t
a
n
3
A
t
a
n
2
A
t
a
n
A
=
t
a
n
2
A
+
t
a
n
A
⇒
t
a
n
3
A
−
t
a
n
2
A
−
t
a
n
A
=
t
a
n
3
A
t
a
n
2
A
t
a
n
A
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Q.
Find the value of tan 3A - tan2A - tanA is equal to ________
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n
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Q.
tan 3A − tan 2A − tan A =
(a) tan 3 A tan 2 A tan A
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(d) None of these
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