Tan3A - tan2A -tanA is equal toA- c tanA tan2A - tan2A tan3A -tan3A tanAB- d none of theseC- a tan 3 A tan 2 A tan AD- b -tan 3 A tan 2 A tan A

The correct option is C (a) tan3A tan2A tanA tan3A tan2A tanA 3A=2A+A ⇒ tan3A = tan(2A+A) = tan2A+tanA/1 tan2A tanA ⇒ tan3A tan3A tan2A tanA = tan2A + tanA ...

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Byju's Answer

Standard XII

Mathematics

Sin(A+B)Sin(A-B)

tan3A - tan2A...

Question

tan3A - tan2A -tanA is equal to

(a) tan3A tan2A tanA

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(b) -tan3A tan2A tanA

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(d) none of these

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Solution

The correct option is A (a) tan3A tan2A tanA

tan3A tan2A tanA
3A=2A+A
$\Rightarrow t a n 3 A = t a n (2 A + A)$
$= \frac{t a n 2 A + t a n A}{1 - t a n 2 A t a n A}$
$\Rightarrow t a n 3 A - t a n 3 A t a n 2 A t a n A = t a n 2 A + t a n A$
$\Rightarrow t a n 3 A - t a n 2 A - t a n A = t a n 3 A t a n 2 A t a n A$

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Similar questions

Find the value of tan 3A - tan2A - tanA is equal to ________

t a n 3 A - t a n 2 A - t a n A = t a n 3 A t a n 2 A t a n A

Q. Prove that:

tan 3 A tan 2 A tan A = tan 3 A - tan 2 A - tan A

Q. Prove:

tan 3 A - tan 2 A - tan A = tan A tan 2 A tan 3 A

Q. tan 3A − tan 2A − tan A =

(a) tan 3 A tan 2 A tan A
(b) −tan 3 A tan 2 A tan A
(c) tan A tan 2 A − tan 2 A tan 3 A − tan 3 A tan A
(d) None of these

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tan3A - tan2A -tanA is equal to

The correct option is A (a) tan3A tan2A tanA tan3A tan2A tanA 3A=2A+A ⇒tan3A=tan(2A+A) =tan2A+tanA1−tan2AtanA ⇒tan3A−tan3Atan2AtanA=tan2A+tanA ⇒tan3A−tan2A−tanA=tan3Atan2AtanA