Tan 6 theta -3 tan 2 theta 2 theta -1- 2 theta-Prove this-

Sec6 θ = (sec2 θ)3 = (1 + tan2 θ)3 = (1)3 + (tan2 θ)3 + 3 × 1 × tan2 θ (1 + tan2 θ) = 1 + tan6 θ + 3 tan2 θ sec2 θ ...

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Range of Trigonometric Ratios from 0 to 90 Degrees

tan 6 theta +...

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tan⁶theta+3tan²theta sec²theta+1=sec²theta.Prove this.

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