Question

TanA and tanB are the roots of $x^2-5x+\frac{1}{2}$=0 . Find the value of tan (A+B)

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Answer 1

We have to find tan(A+B). For that we need tanA+tanB and tanAtanB. We get this from the quadratic.

tanA + tanB = 5

Tan A tan B = $\frac{1}{2}$

$\Rightarrow$ tan(A+B) = $\frac{tanA+tanB}{1-tanAtanB}$

= $\frac{5}{1-\frac{1}{2}}$ = 10