Area of Triangle with Coordinates of Vertices Given
Tangent at th...
Question
Tangent at the point (2√2,3) to the hyperbolax24−y29= 1 meet its asymptotes at A and B, then area of the triangle OAB, O being the origin is
A
6 sq. units
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B
3 sq. units
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C
12 sq. units
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D
2 sq. units
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Solution
The correct option is A6 sq. units Since area of the triangle formed by tangent at any point lying on the hyperbola x2b2−y2b2= 1 and its asymptotes is always constant and is equal to ab. Therefore, required area is 2 X 3=6 square units.