Tangents are drawn from the point P(2,2) to the circle x2+y2=1, touching the circle at A and B. Then equation of circumcircle of △PAB is
A
x2+y2+2x+2y=0
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B
x2+y2−2x−2y=0
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C
x2+y2+2x−2y=0
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D
x2+y2−2x+2y=0
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Solution
The correct option is Bx2+y2−2x−2y=0 For the required circle, P(2,2) and (0,0) will be end points of its diameter. Hence, equation will be (x−2)(x−0)+(y−0)(y−2)=0⇒x2+y2−2x−2y=0