The correct option is B 3
Putting (3, 5) in the equation of the ellipse, we get S1=+ive and S2=0 so that the point (3, 5) lies outside S1=0 and hence two tangents can be drawn through the point (3, 5). The point (3, 5) lies on S2=0 and only one tangent can be drawn. Thus the total no. of tangents passing through (3, 5 ) to the two ellipses is 2+1=3⇒(b).
Ans: 3