wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Tangents are drawn to x2+y2=1 from any arbitrary point P on the line 2x+y4=0. The corresponding chord of contact passes through a fixed point whose coordinates are

A
(14,12)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
(12,1)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(12,14)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
(1,12)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C (12,14)
Let P(a,42a) be any point on 2x+y=4
Equation of chord of contact drawn from P is
T=0xa+y.(42a)=1
(4y1)+a(x2y)=0
the above equation represents family of lines which passes through intersection points of y=1/4 and x=2y

So, the required point is (12,14)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Chord of a Circle
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon