Tangents drawn at the end points of the diameter of a circle are
Here AB is a diameter of the circle with centre O, two tangents PQ and RS drawn at points A and B respectively.
Radius will be perpendicular to these tangents.
Thus, OA ⊥ RS and OB ⊥ PQ
∠OAR=∠OBP=∠OBQ=900
Therefore,
∠OAR=∠OBQ (Alternate interior angles)
∠OAS=∠OBP (Alternate interior angles)
Since alternate interior angles are equal, lines PQ and RS will be parallel.