Tangents drawn from the point P(1, 8) to the circle $x^{2} + y^{2} - 6 x - 4 y - 11 = 0$ touch the circle at the points A and B. The equation of the circum circle of the trianglePAB is

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Solution

The correct option is B
Circum circle of $Δ P A B$ is the circle, having (1, 8) and (3, 2) as end points of diameter.

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Q. Tangents drawn from the point P(1, 8) to the circle

x^{2} + y^{2} - 6 x - 4 y - 11 = 0

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Tangents drawn from the point P(1, 8) to the circle x2+y2−6x−4y–11=0 touch the circle at the points A and B. The equation of the circum circle of the trianglePAB is

The correct option is B Circum circle of ΔPAB is the circle, having (1, 8) and (3, 2) as end points of diameter.

Tangents drawn from the point P(1, 8) to the circle $x^{2} + y^{2} - 6 x - 4 y - 11 = 0$ touch the circle at the points A and B. The equation of the circum circle of the trianglePAB is

The correct option is B
Circum circle of $Δ P A B$ is the circle, having (1, 8) and (3, 2) as end points of diameter.