Tangents from a point P are drawn onto a circle with angle between them as 120∘ . The tangents from P meet the circle at A and B. If a line is drawn from point P through the center of the circle O, the value of ∠POA is
300
The tangent at any point of a circle is perpendicular to the radius through the point of contact.
So, ∠ PAO = 90∘------(1)
Given ∠ APB = 120∘
A line through P passing through O bisects ∠APB
So, ∠ APO = 60∘---------(2)
In APO,
∠ APO + ∠ PAO+∠POA = 180∘
From (1) and (2)
∠ POA = 30∘