Question

Tap on the region in which the probability of finding a crashed plane is $\frac{1}{9}.$

• A.
• B.
• C.

Answer 1

The correct option is A

Probability of plane crashing in a particular area can be found using geometric probability.

$\text{Geometric probability}=\frac{\text{Area of specified region}}{\text{Area of whole region}}$

$\text{Area of the park}=l\times b=18\times 6=108k{m}^2$

$\text{Area of lake}=l\times b=6\times 2=12k{m}^2$

$\text{Area of walking area}=l^2=4^2=16k{m}^2$

$\text{Area of play area}=\frac{\pi r^2}{2}=\frac{4\pi }{2}=2\pi k{m}^2$

$\text{Probability of plane crashing in the}\text{lake}=\frac{\text{Area of lake}}{\text{Area of park}}=\frac{12}{108}=\frac{1}{9}$

$\text{Probability of plane crashing in the}\text{walking area}=\frac{16}{108}=\frac{4}{27}$

$\text{Probability of plane crashing in the}\text{play area =}\frac{2\pi }{108}=\frac{\pi }{54}$

$\therefore \text{~Lake is the area in which the probability}\text{of finding a crashed plane is}\frac{1}{9}.$