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Question

Taruna borrowed twice the money borrowed by Nisha at the same rate of 10% simple interest per annum for 5 years. If Nisha paid Rs.53000 less than the interest paid by Taruna, find the money borrowed by both of them.

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Solution

Let the borrowed money by Jaruna be Rs. x and by Nisha be Rs. y.
Rate =10%,
T=5 years
S.I for Jaruna=P×R×T100
=x×10×5100
=Rs. x2
S.I for Nisha=y×10×5100
=Rs. y2
Amount for Jaruna=SI+x
=Rs. 3x2
For Nisha=Rs. 3y2.
Amount paid by Nisha: 3x23y2=53000
3x3y=1060000 ……….(1)
x=2y ………
x2y=0 ………..(2)
x=2y
=2×35333.3
x=Rs. 70666.6,
Multiplying equation (2)by(3)$
3x3y=106000
3x6y=0
_______________
3y=106000
_______________
y=35333.3 Rs.
Money borrowed by Jaruna =Rs. 70666.6
and by Nisha =Rs. 35333.3.

1162373_1281817_ans_55dc80c6d31e493194eadcd8f46570f0.jpg

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