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<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Arrange the following in increasing order of their metallic character: Si,Na,Mg,P,Be

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Solution

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> We know that metallic character increases down the group and decrease along the period from left to right. Be belongs to 2nd period , where as Na ,Mg,Si,P belong to 3rd period. Be , Na,Mg,Si and P belong to 2,1,2,14 and 15 groups respectively. Therefore Na is the most metallic element,Phosphorus is the least metallic element of the given elements. Mg is more metallic element than Be . Si is more metallic element than P. The increasing order of metallic character is P<Si<Be<Mg<Na.

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