Question

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Calculate the amount of heat energy released when 50 g of water at 90 °C cooled down to 60 °C.

Answer 1

$\text{Specific heat of water}=4.184\text{J/g}$
$\text{Mass of water}=50\text{g}$
$\text{Change in temperature}=30\text{°C}$

$\text{Total heat released}=\text{mass of water}\times \text{specific heat of water}\times \text{change in temperature}$
$=\text{50}\text{g}\times \text{4.184}\text{J/g °C}\times \text{30 °C}$
$=\text{50}\times \text{4.184}\times \text{30 J}$
$=6276\text{J}$
$\therefore \text{6276}\text{J}\text{of heat energy is released when 50 g of water at 90 °C colloed down to 60 °C .}$