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Also so ab+(−c)d−(−c)d+ab=……….
(i) Additive inverse of −5−12=−512.
(ii) −5−12+ its additive inverse =−5−15+(−515) r0.
(iii) If ab is additive inverse of −cd, then −cd is additive inverse of ab.
Also so ab+(−c)d−(−c)d+ab=0.