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Let the shells be n and n+1 (As they are consecutive shells)
Now, 2(n+1)2 - 2n2=10.
Solving this further, we get, 2n2+4n+2−2n2=10.
This further solves to 4n=8.
So, the shell required = 2 and (2+1) = 3.
The alphabetical representation will be L shell and M shell.