Question

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> What is the oxidation number of Manganese in permanganate ion $\left(MnO{4}^{–}\right)$?

Answer 1

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Charge on the permanganate ion is -1
Oxidation state of oxygen = -2

Oxidation state of permanganate ion = (Oxidation state of manganese) + (4 x oxidation state of oxygen) = -1

Oxidation state of manganese = +7