Ted took out his notes and saw following questions-1- Find 9 -52- Find -11 -73- Find -9 -3 -2 - 10Sum of the values obtained in questions 1-2 and 3 is

The correct option is A 508Here, 1) 9× ( 5) = 45, 2) ( 11) × ( 7) = 77, 3) ( 9) × ( 3) × ( 2) × 10 = 540, Adding the values obtained in 1, 2 and 3, nbsp; ...

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Standard VII

Mathematics

Multiplication of Integers

Ted took out ...

Question

Ted took out his notes and saw following questions:
1: Find $9 \times (- 5)$

2: Find $(- 11) \times (- 7)$

3: Find $(- 9) \times (- 3) \times (- 2) \times 10$

Sum of the values obtained in questions $1, 2$ and $3$ is _______.

- 508

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Solution

The correct option is A $- 508$
Here,
$1) 9 \times (- 5) = - 45$ ,
$2) (- 11) \times (- 7) = 77$ ,
$3) (- 9) \times (- 3) \times (- 2) \times 10 = - 540$ ,

Adding the values obtained in 1, 2 and 3,
= - 45 + 77 + (-540)
= 32 - 540
= - 508

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Similar questions

Ted remembered that he had assignments for previous day’s class. He took out his notes and saw the following question :-

Step 1: Find
$9 \times (- 5)$

Step 2: Find
$(- 11) \times (- 7)$

Step 3: Find
$(- 9) \times (- 3) \times (- 2) \times 10$

Step 4:
Add the values obtained in steps 1,2 and 3.

Find the result obtained in step 4.

Question 1 (iv)

Find the sum:
$\frac{- 3}{- 11} + \frac{5}{9}$

Q. Question 11
Find and correct the errors in the statement:

(y - 3)^{2} = y^{2} - 9

Q. Question 19
Find the values of k, if the points A(k+1, 2k), B(3k,2k+3) and C(5k-1,5k) are collinear.

Q. In each of the following questions , one term is wrong. Find out the wrong term.

1, 5, 5, 9, 7, 11, 11, 15, 12, 17

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Ted took out his notes and saw following questions: 1: Find 9×(−5) 2: Find (−11)×(−7) 3: Find (−9)×(−3)×(−2)×10 Sum of the values obtained in questions 1,2 and 3 is _______.

The correct option is A −508Here, 1) 9×(−5)=−45, 2)(−11)×(−7)=77, 3)(−9)×(−3)×(−2)×10=−540, Adding the values obtained in 1, 2 and 3, = - 45 + 77 + (-540) = 32 - 540 = - 508

Ted took out his notes and saw following questions:
1: Find $9 \times (- 5)$

2: Find $(- 11) \times (- 7)$

3: Find $(- 9) \times (- 3) \times (- 2) \times 10$

Sum of the values obtained in questions $1, 2$ and $3$ is _______.

The correct option is A $- 508$
Here,
$1) 9 \times (- 5) = - 45$ ,
$2) (- 11) \times (- 7) = 77$ ,
$3) (- 9) \times (- 3) \times (- 2) \times 10 = - 540$ ,

Adding the values obtained in 1, 2 and 3,
= - 45 + 77 + (-540)
= 32 - 540
= - 508