Question

Teh index of refraction of fused quartz is 1.472 for light of wavelength 400 nm and is 1.452 for hight of wavelength 760 nm. Find the speeds of ight of these wavelengths in fused quartz.

Answer 1

We know that $\frac{{\mu }_2}{{\mu }_1}=\frac{v_1}{v_2}so,\frac{1.472}{1}=\frac{3\times {10}^8}{v}\Rightarrow v_{400}=2.04\times {10}^{8}mm/sec\therefore \text{for air,}\mu =1andv=3\times {10}^{8}m/sAgain,\frac{1,452}{1}=\frac{3\times {10}^8}{v_{760}}\Rightarrow v_{760}=2.07\times {10}^{8}m/sec$