Temperature at which most probable speed of O2 becomes equal to root mean square speed of N2 is:[Given:N2 at 427∘C]
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Solution
Root mean square speed is vr=√3RTM For N2,M=14×2=28 vr=√3RT28=√3×8.314×(427+273)28= Most probable speed is vr=√2RTM For O2,M=16×2=32 vM=√2RTM=√2×8.314×T32 Now, √3×8.314×(427+273)28=√2×8.314×T32 ⇒T=1200K