Temperature of a body - is slightly more than the temperature of the surrounding -0 - Its rate of cooling R versus temperature of body - is plotted- Its shape would be

According to Newton's law of cooling rate of cooling R∝Temperature differenceHence, nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nb ...

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Standard XII

Physics

1st Law of Thermodynamics

Temperature o...

Question

Temperature of a body $θ$ is slightly more than the temperature of the surrounding $θ_{0}$ . Its rate of cooling $(R)$ versus temperature of body $(θ)$ is plotted. Its shape would be

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Solution

The correct option is B

According to Newton's law of cooling rate of cooling R∝Temperature difference
Hence, R = K (θ - θ₀)
This is an equation of a straight line.

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Temperature of a body θ is slightly more than the temperature of the surrounding θ0 . Its rate of cooling (R) versus temperature of body (θ) is plotted. Its shape would be

The correct option is B According to Newton's law of cooling rate of cooling R∝Temperature differenceHence, R = K (θ - θ0)This is an equation of a straight line.

Temperature of a body $θ$ is slightly more than the temperature of the surrounding $θ_{0}$ . Its rate of cooling $(R)$ versus temperature of body $(θ)$ is plotted. Its shape would be

The correct option is B

According to Newton's law of cooling rate of cooling R∝Temperature difference
Hence, R = K (θ - θ₀)
This is an equation of a straight line.