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Question

Temperature of a monoatomic gas is increased from T0 to 2T0 in three different processes : isochoric, isobaric and adiabatic. Heat given to the gas in these processes are Q1,Q2 and Q3 respectively. Then choose the correct option.

A
Q1>Q3
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B
Q2>Q1
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C
Q2>Q3
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D
Q3=0
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Solution

The correct options are
A Q1>Q3
B Q2>Q1
C Q2>Q3
D Q3=0
First law of thermodynamics gives us the relation:
q=ΔU+w
For all three cases ΔU is the same (only a function of temperature).
For isochoric w = 0;
For adiabatic w =ΔU
For isobaric w = positive.
Work done is maximum in isobaric.
i.e.
Q2>Q1>Q3
and Q3=0
Hence all four options are correct.

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