The correct option is B 72∘F,40 K
As ΔT=40∘C, we can choose any 2 temperatures , lets take 0 ∘C & 40∘C .
Now, we have to find corresponding ΔTF in Fahrenheit scale
T∘C=59 (T∘F−32)
Let TF1 and TF2 be the corresponding temperature on Fahrenheit scale.
Then, 0=59 (TF1−32)
⇒TF1=32∘F
Similarly,
40=59 (TF2−32)
⇒TF2=104∘F
∴ΔT∘F=104−32=72∘F
Also, we know ΔT∘C=ΔTK
∴ΔTK=40 K