Temperatures of two hot bodies B1 and B2 are 100-C and 80-C respectively- The temperature of surrounding is 40-C- At t - 0- the ratio of rates of cooling of the two bodies liquid R1 - R2 will be-

The correct option is C 3 : 2 Rate of cooling= dQ dt ∝ Δ T #160; ∴ R _ 1 R _ 2 =Δ T _ 1 Δ T _ 2 = 100 40 80 40 = 60 40 = 3 2 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

System, Surroundings, Intensive, Extensive Properties

Temperatures ...

Question

Temperatures of two hot bodies $B_{1}$ and $B_{2}$ are $100^{\circ} C$ and $80^{\circ} C$ respectively. The temperature of surrounding is $40^{\circ} C$ . At $t = 0$ , the ratio of rates of cooling of the two bodies (liquid) $R_{1} : R_{2}$ will be:

3 : 2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

5 : 4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 : 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 : 5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $3 : 2$
Rate of cooling= $\frac{d Q}{d t} \propto Δ T$
$∴ \frac{R_{1}}{R_{2}} = \frac{{Δ T}_{1}}{{Δ T}_{2}} = \frac{100 - 40}{80 - 40} = \frac{60}{40} = \frac{3}{2}$

Suggest Corrections

Similar questions

Consider two hot bodies $B_{1}$ and $B_{2}$ . which have

temperatures $100^{\circ} C$ and $80^{\circ} C$ respectively at t = 0 .

The temperature of the surroundings is $40^{\circ} C$ .

The ratio of the respective rates of cooling $R_{1} a n d R_{2}$ of these two bodies at t = 0 will be

Q. Consider two hot bodies

B_{1}

and

B_{2}

which have temperatures

100^{\circ} C

and

80^{\circ} C

, respectively at

t = 0

. The temperature of the surroundings is

40^{\circ} C

. The ratio of the respective rates of cooling

R_{1}

and

R_{2}

of these two bodies at

t = 0

will be

Q. Consider two hot bodies

B_{1} a n d B_{2}

which have temperatures

100^{o} C a n d 80^{o} C

respectively at t=0. The temperature of the surroundings is

40^{o} C

. The ratio of the respective rates of cooling

R_{1} a n d R_{2}

of these two bodies at t=0 will be

Q. Consider two hot bodies

B_{1}

and

B_{2}

which have temperatures

100^{\circ} C

and

80^{\circ} C

, respectively at

t = 0

. The temperature of the surroundings is

40^{\circ} C

. The ratio of the respective rates of cooling

R_{1}

and

R_{2}

of these two bodies at

t = 0

will be :

Q. Consider two hot bodies

B_{1}

and

B_{2}

which have temperatures

100^{o} C

and

80^{o} C

respectively at t = 0. The temperature of the surroundings is

40^{o} C

. The ratio of the respective rates of cooling

R_{1}

and

R_{2}

, of these two bodies at t = 0 will be

Join BYJU'S Learning Program

Temperatures of two hot bodies B1 and B2 are 100∘C and 80∘C respectively. The temperature of surrounding is 40∘C. At t=0, the ratio of rates of cooling of the two bodies (liquid) R1:R2 will be:

The correct option is C 3:2Rate of cooling=dQdt∝ΔT ∴R1R2=ΔT1ΔT2=100−4080−40=6040=32

Temperatures of two hot bodies $B_{1}$ and $B_{2}$ are $100^{\circ} C$ and $80^{\circ} C$ respectively. The temperature of surrounding is $40^{\circ} C$ . At $t = 0$ , the ratio of rates of cooling of the two bodies (liquid) $R_{1} : R_{2}$ will be:

The correct option is C $3 : 2$
Rate of cooling= $\frac{d Q}{d t} \propto Δ T$
$∴ \frac{R_{1}}{R_{2}} = \frac{{Δ T}_{1}}{{Δ T}_{2}} = \frac{100 - 40}{80 - 40} = \frac{60}{40} = \frac{3}{2}$