Temporary hardness is due to HCO−3 of Mg2+ and Ca2+. It is removed by addition of CaO. Ca(HCO3)2+CaO→2CaCO3+H2O Mass of CaO (in g) required to produce 2 g of CaCO3 precipitate is:
A
2.00
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B
0.56
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C
0.28
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D
1.12
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Solution
The correct option is A0.56 Molecular weight of CaCO3 and CaO are 100 g/mol and 56 g/mol respectively. 2 equivalents of CaCO3 requires 1 equivalents of CaO.
Amount of CaO required to produce 2 g of CaCO3=2×562×100=0.56