Question

Ten 50 W bulbs are operated on an average for 10 hours a day. The energy consumed in kWh in one month of 30 days is

• A. 50 kWH
• B. 100 kWH
• C. 150kWH
• D. 200 kWH

Answer 1

Answer: (C)

150kWH

$E=i^{2}Rt=Pt$
$i$ - current
$R$ - Resistance
$t$- seconds
$P$ -Power
$E=50\times 10\times 10\times 30$
$=150\times {10}^3$
$E=150kwh$