wiz-icon
MyQuestionIcon
MyQuestionIcon
3
You visited us 3 times! Enjoying our articles? Unlock Full Access!
Question

Ten different books are arranged on a shelf. Find the number of different ways in which this can be done, if 2 specified books are:1) not to be together 2) to be together

Open in App
Solution

There are total 10 books .So total arrangement when there is no restriction = 10!Now we wil take two book together and consider them as 1 so total number of arrangemnet of these 9 books=9!But 2 books considered as one can also interchange their position so, total number of ways = 9!×2!Now when two books are not together then total number of ways = 10!-9!×2!

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Introduction
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon