Question

Ten gram of an alloy of metals A and B contains 7.5 gm of metal A and the rest is metal B. Find the
ratio between:

the weights of metals A and B in the alloy.

Answer 1

We know that

Total weight of A and B metals = 10 gm A weight - 7.5 gm B weight

So we get

= 10 – 7.5

= 2.5 gm

Ratio between the weight of A and B in the alloy = 7.5: 2.5

It can be written as

$=\frac{75}{10}:\frac{25}{10}$

So we get

$=3:1$