wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Ten grams of 60Co kept in an open container β decays with a half-life of 270 days. The decay products are constantly flushed out. The weight of the material inside the container after 540 days will be very nearly:

A
10 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
5 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2.5 g
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
1.25 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 2.5 g
The half-life t12, by definition, is the period of time after which the sample size (number ) becomes half. For 60Co, since t12=270 days, after 270 days, there will be only half the nuclei left after the β decay, and the sample will weigh only 5 g, since you started off with 10 g. So now your sample weighs 5 g, and contains that many nuclei.
After another period of 270 days, half of that will remain, i.e. only 2.5 g. Therefore, after two half-lives, or 540 days, the sample will weigh only 2.5g.
Generally, if you have N0 nuclei in the sample at present, only N02n will remain after n half-life periods, or at t=n×t12,N=N02nThink about it.

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Half and Average Life
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon