Question

Ten men, working for 6 days of 10 hours each, finish $\frac{5}{21}$ of a piece of work. How many men working at the same rate and for the same number of hours each day, will be required to complete the remaining work in 8 days?

Answer 1

Work done $=\frac{5}{21}$
Remaining work $=1-\frac{5}{21}=\frac{16}{21}$
$\frac{5}{21}$ of a work can be done in 6 days working 10 hours a day by = 10 m
1 work can be done in 6 days working 10 hours a day by $=\frac{10\times 21}{5}$
1 work can be done in 1 day working 10 hours a day by $=\frac{10\times 21\times 6}{5}$ men
$\frac{16}{21}$ work can be done in 8 days working 10 hours a day by $=\frac{10\times 21\times 6\times 16}{5\times 21\times 8}=24$ men