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Standard XII
Chemistry
Charles' Law
Ten moles of ...
Question
Ten moles of an ideal gas at constant temperature 600K is compressed from 100 L to 10 L. The work done in the process is
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Solution
Given,
Initial volume,
V
1
=
100
Final Volume,
V
2
=
10
Work done,
W
=
2.3026
n
R
T
l
o
g
10
(
V
2
V
1
)
=
2.3026
×
10
×
8.3
×
600
l
o
g
10
(
10
100
)
=
11.4
×
10
4
J
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