CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Measuring Length and Zero Error

Ten similar c...

Question

Ten similar coins were stacked one above the other. When measured with a scale, the readings at the top and bottom were 1.5 cm and 4.0 cm respectively. What is the thickness of each coin?

Open in App

Solution

Total thickness of 10 coins = 4.0 cm – 1.5 cm
= 2.5 cm

Therefore, thickness of each coin = 2.5 cm ÷ 10
= 0.25 cm

Suggest Corrections

thumbs-up

1

Similar questions

Q. A dozen identical coins were stacked one above the other. Their total height was 3 cm 6 mm.
What is the thickness of one coin?

Q. Ten coins are placed on top of each other on a horizontal table. If the mass of each coin is 10g and acceleration due to gravity is

10 m s^{- 2}

, what s the magnitude and direction of the force on the 7th coin (coloured from the bottom) due to all the coins above it?

Q. Ten coins are placed on top of each other on a horizontal table. If the mass of each coin is

10 gm

, what is the magnitude and direction of the force on the 7th coin (counted from the bottom) due to all the coins above it? Take

g = 10 m / s^{2}

A metal parallelopiped of measures 16 cm

\times

\times

10 cm was melted to make coins. How many coins were made if the thickness and diameter of each coin was 2 mm and 2 cm respectively ?

Q. Ten coins are placed on top of each other on a horizontal table. If the mass of each coin is

10 gm

, what is the magnitude and direction of the force on the

7 t h

coin (counted from the bottom) due to all the coins above it? Take

g = 10 {m/s}^{2}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Measuring Length and Zero Error

PHYSICS

Watch in App

explore_more_icon

Explore more

Measuring Length and Zero Error

Standard VI Physics

Join BYJU'S Learning Program

CrossIcon