Question

Ten tuning fork are arrange in increasing order of frequency in such a way that any two nearest tuning fork produce 4beats per second. The highest frequency is twice that of the lowest .possible highest and lowest frequency are

Answer 1

Let the frequency of first tuning fork is x then then we add on 4 to x to get frequency of next fork so by doing this the frequency of the last fork will be 36+x .
Now since it is given that the frequency of last tuning fork is double than that of first we get other frequency of last tuning fork = 2x
Now by solving these two equations we get
x = 36
therefore least frequency is 36 and max. is 72.