Question

Ten years ago, a father was twelve times as old as his son and ten years hence, he will be twice as old as his son will be then. Find their present ages.

Answer 1

Let the present age of father be x years and the present age of his son be y years.

After 10 years, father’s age will beyears and son’s age will beyears. Thus using the given information, we have

Before 10 years, the age of father wasyears and the age of son wasyears. Thus using the given information, we have

So, we have two equations

Here x and y are unknowns. We have to solve the above equations for x and y.

By using cross-multiplication, we have

Hence, the present age of father isyears and the present age of son isyears.