Question

Ten years ago, father was twelve times as old as his son. Ten years after, he will be twice as old as his son will be. Find their present ages in years

• A. 12, 36
• B. 12, 24
• C. 12, 34
• D. None of these

Answer 1

The correct option is C 12, 34

Let ten years ago the age of son and father were $x$ and $12x$ years.

Then, $2(x+20)=12x+20$

$\Rightarrow 10x=20\Rightarrow x=2$

Their present ages are

$x+10=2+10=12years$

$12x+10=24+10=34years$.