Ten years ago , P was half of Q's age. If the ratio of their present ages is 3:4. What will be the total of their present ages

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Solution

Let the present age of P and Q be 3x and 4x respectively.
Ten years ago, P was half of Q in age
=> 2(3x – 10) = (4x – 10)

=> 6x – 20 = 4x – 10

=> 2x = 10

=> x = 5
present age of p=3x
3 x 5=15
present age of q=4x
4 x 5=20
total of their present ages =15+20=35

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Ten years ago , P was half of Q's age. If the ratio of their present ages is 3:4. What will be the total of their present ages

Let the present age of P and Q be 3x and 4x respectively. Ten years ago, P was half of Q in age => 2(3x – 10) = (4x – 10) => 6x – 20 = 4x – 10 => 2x = 10 => x = 5 present age of p=3x 3 x 5=15 present age of q=4x 4 x 5=20 total of their present ages =15+20=35

Let the present age of P and Q be 3x and 4x respectively.
Ten years ago, P was half of Q in age
=> 2(3x – 10) = (4x – 10)

=> 6x – 20 = 4x – 10

=> 2x = 10

=> x = 5
present age of p=3x
3 x 5=15
present age of q=4x
4 x 5=20
total of their present ages =15+20=35