Question

Tendency to loss electrons shows the reducing property of the element. Which of the following orders is/are correct in terms of reducing property of the element?

• A. $Na<K<Rb$
• B. $Na>Mg>Al$
• C. $F^{-}<C{l}^{-}<B{r}^{-}<I^{-}$
• D. $Mg<Ca<Sr$

Answer 1

Answer: (A), (B), (C), (D)

The correct options are
A $Na<K<Rb$
B $Na>Mg>Al$
C $F^{-}<C{l}^{-}<B{r}^{-}<I^{-}$
D $Mg<Ca<Sr$

All the options (A to D) represent the correct order of reducing property.

(A) $Na<K<Rb$: On moving down the group, the electropositive character increases and the reducing character increases.

(B) $Na>Mg>Al$: In a period from left to right, the electropositive character decreases and the reducing character decreases.

(C) $F^{-}<C{l}^{-}<B{r}^{-}<I^{-}$: With the increase in the size of halide ion, the electropositive character increases and the reducing character increases.

(D) $Mg<Ca<Sr$: On moving down the group, the electropositive character increases and the reducing character increases.

Hence, the correct options are $\text{A, B, C}$ and $\text{D}$