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Perfectly Elastic Collision

Tension in st...

Question

Tension in string immediately after the first collision is:

2 m g

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m g

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\frac{3}{2} m g

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\frac{5}{2} m g

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Solution

The correct option is C $\frac{3}{2} m g$
Conservation of momentum $= \frac{m}{2} \sqrt{2 g l} = m \cdot v$
$v = \sqrt{\frac{g l}{2}}$
Now, $T = \frac{m v^{2}}{l} + m g$
$= \frac{m g l}{2 g l} + m g = \frac{3}{2} m g$

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Tension in string immediately after the first collision is:

The correct option is C 32mgConservation of momentum =m2√2gl=m⋅vv=√gl2Now, T=mv2l+mg=mgl2gl+mg=32mg

The correct option is C $\frac{3}{2} m g$
Conservation of momentum $= \frac{m}{2} \sqrt{2 g l} = m \cdot v$
$v = \sqrt{\frac{g l}{2}}$
Now, $T = \frac{m v^{2}}{l} + m g$
$= \frac{m g l}{2 g l} + m g = \frac{3}{2} m g$