Tension in the rope at the rigid support is $(g = 10 m / s^{2})$ :

760 N

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1360 N

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1580 N

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1620 N

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Solution

The correct option is C $1580 N$
The correct option is C

For case 1

When the man ascends up the rope with the acceleration of $2 m / s^{2}$

We have,

$T_{1} - m g = m a$

$T_{1} = m g + m a$

$T_{1} = 600 + (60 \times 2)$

$720 N$

In case 2

When the mass descends by the constant velocity,

We have $T_{2} = m g$

$T_{2} = 50 \times 10 = 500 N$

Case 3

We have $m g - T = m a$

$T = m g - m a$

So,

$T_{3} = 400 - (40 \times 1) = 360 N$

So the net tension at the rigid support is

$720 N + 360 N + 500 N = 1580 N$

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