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Question

Tenth fringe of wavelength 4000Ao coincides with 8th fringes of wavelength λ. Then λ is

A
50nm
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B
555nm
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C
450nm
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D
none
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Solution

The correct option is D none
Since 10 fringes of λ1 coincide with 8 fringes of λ2,
10β1=8β2
10×Dλ1d=8×Dλ2d
λ=108×4000A
λ=500nm

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