Teritary alcohol is obtained as major product in

(C H_{3})_{2} C H - C H = C H_{2} o x y m e r c u t i o n / d e m e r c u t i o n \to

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(C H_{3})_{3} C - C H = C H_{2} d i l H_{2} S O_{4} \to

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(C H_{3})_{2} C H - C H = C H_{2} H y d r o b o r a t i o n, O x i d a t i o n \to

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All of the above

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Solution

The correct option is B $(C H_{3})_{3} C - C H = C H_{2} d i l H_{2} S O_{4} \to$
Tertiary alcohol is obtained when an alkene reacts with dilute sulphuric acid.

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Similar questions

(C H_{3})_{2} C H - C H = C H - C H = C H - C | H C_{2} H_{5} - C H_{3}

The IUPAC name of this is:

The correct order of stability of the following carbanions is:

$(C H_{3})_{3} C^{-},^{-} C C l_{3}, (C H_{3})_{2} C H^{-}, C_{6} H_{5} - C H_{2}^{-}$

The arrangement of $(C H_{3})_{3} C -, (C H_{3})_{2} C H -, C H_{3} C H_{2} -$ When attached to a benzene or an unsaturated group in increasing order of inductive effect is:

Consider the reactions

(i) $(C H_{3})_{2} C H - C H_{2} B r C_{2} H_{5} O H - ---- \to (C H_{3})_{2} C H - C H_{2} O C_{2} H_{5} + H B r$

(ii) $(C H_{3})_{2} C H - C H_{2} B r C_{2} H_{S} O^{-} - ---- \to (C H_{3})_{2} C H C H_{2} O C_{2} H_{5} + B r^{-}$

The mechanism of reactions (i) & (ii) are respectively

Q. A compound

^{'} X^{'}

having molecular formula

C_{5} H_{8}

, reacts with ammoniacal

A g N O_{3}

to give a white precipitate and reacts with excess of

K M n O_{4}

to give the acid,

(C H_{3})_{2} C H - C O O H

. Therefore,

X

is:

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Teritary alcohol is obtained as major product in

The correct option is B (CH3)3C−CH=CH2dilH2SO4→Tertiary alcohol is obtained when an alkene reacts with dilute sulphuric acid.

The correct option is B $(C H_{3})_{3} C - C H = C H_{2} d i l H_{2} S O_{4} \to$
Tertiary alcohol is obtained when an alkene reacts with dilute sulphuric acid.