Test scores of Jonathan and Jameson is given. From the information, the average marks of Jonathan is the mean of Jameson.

\begin{tabular}{|c|c|c|c|c|c|} \hline Test scores of Jonathan (in \%) & 82 & 75 & 82 & 96 & 75 \\ \hline Test scores of Jameson (in \%) & 95 & 70 & 75 & 74 & 96 \\ \hline \end{tabular}

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Solution

The correct option is C =
The given chart is

The data set is (Jonathan)

82, 75, 82, 96, 75

The mean of the data set is the sum of the data divided by the number of data values

Mean = $\frac{s u m o f a l l d a t a}{n u m b e r o f d a t a}$

Mean = $\frac{82 + 75 + 82 + 96 + 75}{5}$

= $\frac{410}{5}$ = 82

Let us find the mean of Jameson's scores.

The data set is

95, 70, 75, 74, 96

Mean = $\frac{s u m o f a l l d a t a}{n u m b e r o f d a t a}$

Mean = $\frac{95 + 70 + 75 + 74 + 96}{5}$

= $\frac{410}{5}$ = 82

Hence, the mean of the marks of Jonathan and Jameson are equal.

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